Here is proof of flat earth

by BenyFootworn
(Sacramento, CA, USA)

Here is flat earth proof. The fact that an observer can see the Chicago skyscrapers 60 miles away across Lake Michigan when the skyline should be hidden behind the curvature of the earth. The Chicago skyline has skyscrapers about 1,400 feet high.

The observer across the lake and the base of Chicago are both at about 600 feet above sea level. According to Earth Curve Calculator an observer across the lake conservatively at 100 feet high will see the horizon about 12 miles away beyond which everything is hidden. Curve Calculator also says a 100 foot high observer can’t see anything beyond the horizon that is less than about 1,400 feet high.

Yet, the Lake Michigan observer at about 60 miles away can see practically all of the about 1,400 foot tall skyscrapers. So the earth is flat because there is not any earth curvature that is supposed to block the view of the skyscrapers. Some have tried to debunk seeing the skyscrapers by attributing this to a super mirage. But, this is false because a super mirage would cause one to see an inverted image of the skyscrapers.

Earth Curve Calculator,
https://dizzib.github.io/earth/curve-calc/?d0=60&h0=100&unit=imperial

Can see Chicago skyscrapers 60 miles away, "Chicago Skyline Visible from 60 Miles? Superior Mirage at Work?",
http://investigate-nasa.com/2015/11/12/earth-curve-calculator/

Super mirage does not explain seeing skyscrapers, "Superior Mirages",
http://investigate-nasa.com/2015/11/12/superior-mirages/

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Mar 28, 2017
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Flat earth nonsense
by: Ray

You assume two things which are not necessarily true. #1: That there is no refraction involved (that picture that is passed around by flatters on youtube is of a rare anomalous atmospheric event). #2: That the picture was taken at 100ft above the lake. (There are some dunes 58 miles away where you are 200ft = 0.03788mi up).
But lets calc the obscurred part w/o any refraction effect. Assuming an earth of 3859mi radius. The horizon is sqrt(0.03788mi x 7918mi)= 17.32 mi away, From there to the Willis Tower is 58mi-17.32mi=40.68mi. The tangent,(the line of sight) at Willis tower is (40.68mi^2)/7918mi = 0.2090mi = 1104 ft up. Willis tower is 1730 ft to the tip that leaves over 600 ft to see. That is w/o ANY refraction, and there is ALWAYS refraction involved. For just everday normal average refraction, replace the diameter of earth in the calcs with 9000 mi. Now, with everyday average refraction you will see 813 ft of the top, or half if the building. But AGAIN, the pictures you saw were NOT "average everyday refraction", they were pictures of very rare atmospheric events where there was much more refraction than normal.
You are seeing nothing here that is not consistent with a round earth of a diameter of 7918 mi.
By the way, if earth IS flat, why are part of the buildings obscured? I notice that you do admit that they are! If earth is flat and you are standing 200 ft high, you are going to be able to actually see below the bottom of the buildings, but if you look at those pictures knowing their height, and width, you can obviously demo that we are not seeing all of the building. Why, if earth is flat?????

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